Sunday, 26 September 2021

MCA DCA6102 SET 1 MANIPAL JAIPUR UNIVERSITY

 

SESSION

FEB/MAR 2021

PROGRAMME

MASTER OF COMPUTER APPLICATION (MCA)

SEMESTER

I

COURSE CODE & NAME

DCA6105 - COMPUTER ARCHITECTURE

 

 

1.      What do you understand by parallelism in computer architecture? Discuss the different classes of parallelism and parallel architectures?

 

Ans 1.

Parallel Computing: 

It is the use of multiple processing elements simultaneously for solving any problem. Problems are broken down into instructions and are solved concurrently as each resource that has been applied to work is working at the same time. 

1.      It can be impractical to solve larger problems on Serial Computing. 

 

Its Half solved only

Buy Complete from our online store

 

Manipal University

Fully solved assignment available for session Feb/March 2021,

 

your last date is 31th July 2021.

https://ssl.gstatic.com/ui/v1/icons/mail/images/cleardot.gif

Lowest price guarantee with quality.

Charges INR 150 only per assignment. For more information you can get via mail or Whats app also


Mail id is 
aapkieducation@gmail.com

 

Our website www.aapkieducation.com

After mail, we will reply you instant or maximum

1 hour.

Otherwise you can also contact on our

whatsapp no 8791490301.

Contact no is +91 87-55555-879

 

 

2.      What do you understand by process and threads? Differentiate between them?

Answer:

Process: 
Process means any program is in execution. Process control block controls the operation of any process. Process control block contains information about processes for example Process priority, process id, process state, CPU, register, etc. A process can create other processes which are known as Child Processes. Process takes more time to terminate and it

 

 

 

3.      Explain Amdahl’s Law of computer design.

Answer:

Amdahl’s Law:

In computer architectureAmdahl's law (or Amdahl's argument) is a formula which gives the theoretical speedup in latency of the execution of a task at fixed workload that can be expected of a system whose resources are improved. 

In computer architectureAmdahl's law is a formula which It is named after computer

 

 

 

 

 

 

SESSION

FEB/MAR 2021

PROGRAMME

MASTER OF COMPUTER APPLICATION (MCA)

SEMESTER

I

COURSE CODE & NAME

DCA6104 – ADAVANCED DATABASE MANAGEMENT SYSTEMS

 

 

 

 

1.      Consider two tables named ‘Student’ and ‘Course’ as follows

Table: Student       

 

 

(a) Find the Cartesian Product of Tables ‘Student’ and ‘Course’.       

 (b) What will be the result after the successful execution of the following Relational Algebra Expressions?

            • σ age> 18(Student)          


 

 

Reg-No

Name

Age

 

 

 

 

 

R1

A

18

 

R2

B

20

 

R3

C

19

 

R4

D

17

 

Table: Course

 

Course_No

Course_Name

 Credits

 

DCA6104

 ADBMS

 4

 

DCA6103

 CSA

 3

 

DCA6101

 Programing in C

 4

 

 

 

Its Half solved only

Buy Complete from our online store

 

Manipal University

Fully solved assignment available for session Feb/March 2021,

 

your last date is 31th July 2021.

https://ssl.gstatic.com/ui/v1/icons/mail/images/cleardot.gif

Lowest price guarantee with quality.

Charges INR 150 only per assignment. For more information you can get via mail or Whats app also


Mail id is 
aapkieducation@gmail.com

 

Our website www.aapkieducation.com

After mail, we will reply you instant or maximum

1 hour.

Otherwise you can also contact on our

whatsapp no 8791490301.

Contact no is +91 87-55555-879

 

 

 

 

 

 

Answer:

(a) Find the Cartesian Product of Tables ‘Student’ and ‘Course’.

 

Reg-No.

Name

Age

Course_No

Course_Name

Credits

R1

A

18

DCA6104

ADBMS

4

R1

A

18

DCA6103

CSA

3

R1

A

18

DCA6101

Programing in C

4

R2

B

20

DCA6104

ADBMS

4

R2

B

20

DCA6103

CSA

3

R2

B

20

DCA6101

Programing in C

4

R3

C

19

DCA6104

ADBMS

4

R3

C

19

DCA6103

CSA

3

R3

C

19

DCA6101

Programing in C

4

R4

D

17

DCA6104

ADBMS

4

R4

D

17

DCA6103

CSA

3

R4

D

17

DCA6101

Programing in C

4

 

 

(b) What will be the result after the successful execution of the following Relational Algebra Expressions?

 • σ age> 18(Student)

             

Reg-No.

Name

Age

Course_No

Course_Name

Credits

R2

B

20

DCA6104

ADBMS

4

R2

B

20

DCA6103

CSA

3

R2

B

20

DCA6101

Programing in C

4

R3

C

19

DCA6104

ADBMS

4

R3

C

19

DCA6103

CSA

3

R3

C

19

DCA6101

Programing in C

4

 

                        πNameage> 18(Student))

B

C

 

                         

2.      What do you mean by Primary Key, Composite Key and Foreign Key Attributes/Fields? Explain by taking a suitable example of each.

 

Answer:

Primary Key

PRIMARY KEY in DBMS is a column or group of columns in a table that uniquely identify every row in that table. The Primary Key can't be a duplicate meaning the same value can't appear more than once in the table. A table cannot have more than one primary key.

Rules for defining Primary key:

  • Two rows can't have the same primary key value

 

 

 

 

3.      Assume all the relations/tables as mentioned in Q1 are available for this question. Suppose we defined a new third relation named ‘ Registration’ as follows:

Table: Course

Course_No

Course_Name

Credits

DCA6104

ADBMS

4

DCA6103

CSA

3

DCA6101

Programing in C

4

 

Table: Registration

 

Reg-No

 Course No

 Room

 

R1

 DCA6104

 1

 

R1

 DCA6103

 2

 

R2

 DCA6104

 1

 

R2

 DCA6103

 2

 

 

 

 

 

 

 

Explain all forms of ‘join’ operator (such as ‘natural join’, ‘left outer join’ , ‘ right outer join’ and ‘full outer join’) of Relational Algebra using ‘Registration’ and ‘Course’ tables/relations as examples.

 

Answer:

1. Natural Join:

Natural Join joins two tables based on same attribute name and datatypes. The resulting table will contain all the attributes of both the table but keep only one copy of each common column.

 

INTERNAL ASSIGNMENT SET-I

SESSION

FEB/MAR 2021

PROGRAMME

MASTER OF COMPUTER APPLICATIONS (MCA)

SEMESTER

I

COURSE CODE & NAME

DCA6103 – FOUNDATION OF MATHEMATICS

 

1.    a) Out of 30 students in dormitory, 15 take an art course, 8 take a biology course of 6 take a chemistry course. It is known that 3 students take all the three courses. Show that 7 or more students take none of the courses.

Ans 1.

There are total 30 students.

Out of which 3 took all the three courses. So, students remained = 30 - 27.

Students who took arts course = 15, out of these 15 students, 3 students are also included who took all the three courses.

Students who took biology course = 8, out of these 8 students, 3 students are also included

Its Half solved only

Buy Complete from our online store

 

Manipal University

Fully solved assignment available for session Feb/March 2021,

 

your last date is 31th July 2021.

https://ssl.gstatic.com/ui/v1/icons/mail/images/cleardot.gif

Lowest price guarantee with quality.

Charges INR 150 only per assignment. For more information you can get via mail or Whats app also


Mail id is 
aapkieducation@gmail.com

 

Our website www.aapkieducation.com

After mail, we will reply you instant or maximum

1 hour.

Otherwise you can also contact on our

whatsapp no 8791490301.

Contact no is +91 87-55555-879

 

 

 

2.    a) Simplify the following statements:

Answer:

(Using by DeMorgan's Double Negation Laws)

= ~p ˄ q

= p ˅ ~q

 

 

 

 

          3. a) Find the nth derivative of 𝒆𝒙(𝟐𝒙+𝟑)𝟑

                         

                        Answer:

                         

                        𝒆𝒙(𝟐𝒙+𝟑)𝟑= y

 

 

                         

b) Evaluate: ∫ (𝟑𝒕 + 𝟓)co𝒔 (𝒕/𝟒) dt

∫udv = uv - ∫vdu

u = 3t+5 ⇒ du = 3dt

 

SESSION

FEB/MAR 2021

PROGRAMME

MASTER OF COMPUTER APPLICATION (MCA)

SEMESTER

I

COURSE CODE & NAME

DCA6102 – PROGRAMMING IN C

 

 

Q1. a) Explain Structure of a C Program.

b) Explain various constants used in C Programming with example.

Ans 1.

1.                  a) Explain the Structure of a C Program.

The structure is a group of variables of different data types represented by a single name.

Basically structure of the C program is divided into six different sections,
i. Documentation sectionThe Documentation section consists of a set of comment lines.

ii. Link sectionThe link section provides instruction to the compiler to link the header files or functions from the system library. Its Half solved only

Buy Complete from our online store

Manipal University

Fully solved assignment available for session Feb/March 2021,

 

your last date is 31th July 2021.

https://ssl.gstatic.com/ui/v1/icons/mail/images/cleardot.gif

Lowest price guarantee with quality.

Charges INR 150 only per assignment. For more information you can get via mail or Whats app also


Mail id is 
aapkieducation@gmail.com

 

Our website www.aapkieducation.com

After mail, we will reply you instant or maximum

1 hour.

Otherwise you can also contact on our

whatsapp no 8791490301.

Contact no is +91 87-55555-879

 

 

 

Q2. a) Explain bitwise operators with example.

b) What do you understand by precedence and associativity of an operator. Explain with example.

Ans 2.

a) Explain bitwise operators with examples.

The following table lists the Bitwise operators supported by C. Assume variable 'A' holds 60 and variable 'B' holds 13, then −

 
 
 

b) What do you understand by precedence and associativity of an operator? Explain with example.

Operator precedence:

It determines which operator is performed first in an expression with more than one operators with different precedence.

For example: Solve

10 + 20 * 30

 

 

Q3 a) What do you understand by type casting. Explain with example.

b) Explain unformatted and formatted input and output functions with example.

Answer:

3. a) What do you understand by type casting? Explain with example.

A type cast is basically a conversion from one type to another. There are two types of type conversion:

1.      Implicit Type Conversion

https://media.geeksforgeeks.org/wp-content/cdn-uploads/Implicit-Type-Conversion-in-c.png

Also known as ‘automatic type conversion’.

·         Done by the compiler on its own, without any external trigger from the user.

 

 

No comments:

Post a Comment