Sunday, 13 May 2018

smu mca 2nd sem assignment spring 2018 (july/aug 2018 exam)


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DRIVE
Spring 2018
PROGRAM
MASTER OF COMPUTER APPLICATION
SEMESTER
II
SUBJECT CODE & NAME
MCA211 – OPERATING SYSTEM


Set 1
Q1 Differentiate between Sequential access and Direct access methods. 5+5
Answer.

Sequential access and Direct access methods

Sequential access

In this simple access method, information in a file is accessed sequentially one record after another. To process the ith record all the i-1 records previous to i must be accessed. Sequential access is based


Q2 Differentiate between Daisy chain bus arbitration and Priority encoded bus arbitration. 5+5
Answer.

Daisy chain bus arbitration and Priority encoded bus arbitration

There are many ways of addressing the “bus arbitration” problem; three techniques which are often implemented in processor systems are the following: Daisy chain arbitration, priority encoded




Q3. Explain LRU page replacement algorithms with an example 4+6= 10
Answer:
LRU page replacement algorithm
The main distinction between FIFO and optimal algorithm is that the FIFO algorithm uses the time when a page was brought into memory (looks back) whereas the optimal algorithm uses the time when a page is to be used in future (looks ahead). If the recent past is used as an approximation

Set 2
Q1. Define operating system. Explain any four major functions of operating system 2+8 = 10
Answer: Operating System is a System Software (Set of system programs) which provides an environment to help the user to execute the programs. An operating system (OS) is a software program that manages the hardware and software resources of a computer. A key component of system software



Q2 Explain the different process states. 5*2
Answer.

Different process states

A program in execution is a process. A process is executed sequentially, one instruction at a time. A program is a passive entity.

Example: a



Q3 Define Deadlock. Explain necessary conditions for deadlock. 2+(2*4)
Answer.


Deadlock

Deadlock occurs when we have a set of processes [not necessarily all the processes in the system], each holding some resources, each requesting some resources, and none of them is able to obtain what it needs, i.e. to make progress. We will usually reason in terms of resources R1, R2... Rm and

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DRIVE
Spring 2018
PROGRAM
MASTER OF COMPUTER APPLICATION
SEMESTER
II
SUBJECT CODE & NAME
MCA212- ADVANCED DATA STRUCTURE

Set-1

Q1. List and explain any Five types of graph. [5*2]= 10

Answer:

Types of Graphs
Depending upon the vertices and edges and the weight associated to it, graphs can be classified as:
1)      Undirected graph: In Undirected Graph, the directions of edges are not assigned. Edges in the


Q2. Explain
1. Fixed block storage allocation.
2. Variable block storage allocation [5+5] = 10

Answer:


Fixed block storage allocation
First block storage allocation is the simplest case of dynamic storage allocation. This is the straight forward

Q3. What is the use of external Storage Devices? Explain any two external storage devices [4+3+3]=10

Answer:
An external storage device may be defined as device other than the main memory on which information or data can be stored and from which the information retrieved for processing. External storage devices are having larger capacities and fewer expenses to store


Set 2

Q1. Define algorithm and write a note on Complexity and Time- Space Tradeoff with example
[2+4+4]=10

Answer:

Definition: An algorithm is a step by step procedure for solving a particular problem. One major purpose of this text is to develop efficient algorithms for the processing of our data. The efficiency of the algorithm is depending on the time and space it uses. The

Q2. Define Queue and explain
a. Array implementation of queue
b. Linked list implementation of queue

Answer:
A queue is a linear list of elements in which deletions can take place only at one end, called the front and insertions can take place only at the other end, called the rear as referred in the



Q3. List the Advantages and Disadvantages of Linear and linked representation of tree. [5+5] = 10

Answer:

Advantages of linear representation of binary tree
1) Node can be accessed directly with the help of the index through which we can improve the efficiency of execution time of an algorithm.
2) Data


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DRIVE
Spring 2018
PROGRAM
MASTER OF COMPUTER APPLICATION
SEMESTER
II
SUBJECT CODE & NAME
MCA213- OBJECT ORIENTED PROGRAMMING – C++

Set 1
Q1. What are the advantages of Polymorphism? How it can be implemented? 5+5=10
Answer: Advantages
·         Code is simpler to write (
·          
Q2. Differentiate between Containers and Iterators 5+5= 10
Answer: Containers
STL provides a number of container types, representing objects that contain other objects. The STL contains sequence containers and associative containers. The standard sequence containers include vector,

Q3. Describe the two basic exception handling models. 5+5= 10
Answer: If you encounter an exceptional situation in your code – that is, one where you don’t have enough information in the current context to decide what to do – you can send information about the error into a larger


Set 2
Q1. Write short notes on:
a) Inheritance
b) Polymorphism 5+5 = 10
Answer:
A) Inheritance
Inheritance is one of the most powerful features of Object Oriented Programming Languages that allows you to derive a class from an existing class and inherit all the characteristics and


Q2. Differentiate between Classes and Objects. Write an example program to represent a class and its object. 4+6= 10
Answer:
Classes and objects are separate but related concepts. Every object belongs to a class and every class

Q3. Describe operator overloading. Which are the operators that cannot be overloaded?
5+5= 10
Answer: Operator overloading is an interesting feature of C++ that allows programmers to specify how various arithmetic, relational and many other operators work with user defined data types or classes


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Spring 2018 ASSIGNMENT
PROGRAM – MCA (REVISED FALL 2012)
SEMESTER - II
SUBJECT CODE & NAME - MCA214- COMMUNICATION SKILLS
Q. No.1 What is nonverbal communication? Give five examples for non-verbal communication. 5+5= 10
Answer: Non-verbal communication
Non-verbal communication means the messages that do not contain words.
In this type of communication, words are not used in the process of sending and receiving messages. It is a


Q2. What are the prosodic features of speech? 10
Answer:  Prosodic features (sometimes known as suprasegmental phonology) are those aspects of speech which go beyond phonemes and deal with the auditory qualities of sound. In spoken


Q3. Define hearing and Listening. How is ‘hearing’ different from ‘listening’ 4+6= 10
Answer:

Hearing is a passive process. It is merely the detection of sounds around us. Normally, we come across ‘hearing’ in certain situations. E.g.: When your lecturer reprimands you for some of your

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Spring 2018 ASSIGNMENT
PROGRAM - MCA (REVISED FALL 2012)
SEMESTER - SECOND
SUBJECT CODE & NAME - MCA215- COMPUTER ARCHITECTURE

Set 1
Q1. Explain the concept of branch handling. What is delayed branching? 5+5= 10

Answer:
Branch Handling
Branch is a flow


Q2. Explain any five types of vector instructions in detail.5*2= 10

Answer: Types of Vector Instructions:
(a)      Vector-scalar instructions: Using these instructions, a scalar operand can be combined with a vector one. If A and B are vector registers and f is a function that performs some operation on each element of a single or two vector operands, a vector-scalar operand



Q3. Write short notes on:
a) UMA
b) NUMA 5+5= 10

Answer:
a)      UMA (Uniform Memory Access):
In this category every processor and memory module has similar access time. Hence each memory word can be read as quickly as other memory word. If not then quick references are slowed down to match the slow ones, so that programmers cannot find the difference this is called

Set 2


Q1. Differentiate between Process and Thread. 5+5=10

Answer:
Concept of process
In operating system terminology, instead of the term ‘program’, the notion of process is used in

Q2. Explain the any five types of addressing modes. 5*2= 10
Answer:

Every instruction of a computer states an operation on certain data. There are a numerous ways of specifying address of the data to be operated on. These different ways of specifying


Q3. Describe the logical layout of both RISC and CISC computers 5+5= 10
Answer:

While processing operates instructions, RISC pipelines have to cope only with register operands. By contrast, CISC pipelines must be able to deal with both register and memory


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