SPRING
2014 ASSIGNMENT
PROGRAM - Master of Science
in Information Technology (MSc IT)Revised Fall 2011
SEMESTER - 2
SUBJECT CODE & NAME –
MCA4040- ANALYSIS AND DESIGN OF ALGORITHMS
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4 BK ID B1480 MAX. MARKS 60
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Q. No. 1 Write
the steps involved in analyzing the efficiency of non-recursive algorithms. 10
Answer:
The steps involved in
analyzing the efficiency of non-recursive algorithms are as follows:
Decide the input size based on the constraint n
Identify the basic operations of algorithm
2 Define
selection sort and explain how to implement the selection sort? 3+7=10
Answer:
Definition: Selection sort is one of the
simplest and performance oriented sorting techniques that work well for small
files. It has time complexity as O(n2) which is unproductive on large lists.
3 What is mean
by Topological sort? And explain with example. 5+5=10
Answer: Topological sort is done
using a directed acyclic graph (DAG), which is a linear ordering of all
vertices G= (V, E) is an ordering of all vertices such that if G contains an
edge (u, v), then u appears before v in the ordering. A topological sort of a
particular graph can be looked upon as a horizontal line where all directed
edges travel from left to right. Thus, topological sort
4. Explain
good-suffix and bad-character shift in Boyer-Moore algorithm. 5+5=10
Answer: Good suffix Shift
This shift helps in shifting a matched
part of the pattern, and is denoted by Q. Good suffix shift Q is applied after
0 < k < m characters are matched.
Q = distance between matched suffix of
size k and its rightmost occurrence in the pattern that is
5 Solve the
Knapsack problem using memory functions.
Item 1 2 3 4
Weight 2 6 4 8
Value (in Rs.)
12 16 30 40
Knapsack
capacity is given as W=12. Analyze the Knapsack problem using memory functions with
the help of the values given above. 10
Answer:
Knapsack Problem by Memory
Functions
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6 Any NP problem
can be converted into SAT (Satisfiability problem) in polynomial time. Explain
in detail. 4+6=10
Answer: Stephen Cook in 1971 stated
that
“Any NP problem can be converted into SAT (Satisfiability
problem) in polynomial time”
Satisfiability problem SAT – This is a decision problem
whose instance uses only AND, OR and
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