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DRIVE SPRING 2017
PROGRAM Bachelor of Science
in Information Technology - B.SC(IT)
SEMESTER I
SUBJECT CODE & NAME
BIT102 – Digital Electronics
Assignment Set -1
1 Convert the following hexadecimal
numbers to base 10:
a. 145
b. A2C1
Answer: a. 14516 in
Hexadecimal number system and we want to translate it into Decimal.
14516 = 1*16^2+4*16^1+5*16^0
=
256+64+5
2 Construct XOR and NAND Gate using NOR
Gate.
Answer: a)
3 Simplify f (a, b, c, d) = Σm(0, 2, 4,
6, 7, 8, 9, 11, 12, 14)
Answer: The given function is:
f(a.b.c.d)=
∑m(0,2,4, 6,7,8,9,11,12,14)
This
is a four variable function so the k
Assignment Set -2
1 Write a short note on J-K Master Slave
Flip-Flop.
Answer: J-K Master Slave Flip Flop
The logic
symbol for the master-slave flip-flop only indicates the initial inputs to the
master and the outputs from the slave as
2 Explain the working of 4 bit Johnson
counter with the help of neat diagram.
Answer: A Johnson counter is constructed using serial-in
and serial-out (SISO) shift register. The output of the shift register is
connected back to the input after passing it through an inverter. Depending on
the initial bit pattern stored in the shift register, the shift register
content changes for every clock and the bit pattern gets repeated after 2n
clocks, where n is the number of bits in the shift register. These are called
“walking ring” counters and have specialist applications like digital-to-analog
converters (DAC) etc. Many user applications require counter outputs in the
form of decimal digits in place of binary format. One way to get it is by using
a decoder that decodes the binary output and converts it
3 Explain BCD adder and BCD subtractor.
Answer: BCD Adder
The
addition in BCD can be performed in three steps: 1) Add the numbers in binary.
2) Check if the number is greater than 9. 3) Then convert the sum of two
numbers to BCD number by adding correction value. The correction value will be
equal to 6 if the sum output in step 1 is greater than 9, else the correction
value will be zero. For example: 8 + 6 = 14 = [1000] + [0110] = [0000 1110] in
binary. However, in BCD, per \
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